Question

4th under root5× CUBE under root6
$\sqrt[4]{5} \times \sqrt[3]{6}$
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Answer 1

5^(1/4)*6^(1/3)

=5^(3/12)*6^(4/12)

=125^(1/12)*1296^(1/12)

=(125*1296)^1/12

=(162000)^(1/12)

Twelfth root over 162000