4th vertex of the rhombus whose 3 consecutive vertices are (-4,-0),(3,-1),(2,6) is
1) (-5,7)
2) (7,-5)
3) (2,-5)
4)(5,-2)
i want the written answer please
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Answer:
(1, 6)
Step-by-step explanation:
diagonals of parallelogram bisect each other
let the point of intersection of diagonals be p(m,n)
m=(-4+2)/2 = -1
n=(0+6)/2 = 3
let the fourth vertex of parallelogram (x, y)
m=(3+x) /2
-1=(3+x) /2
x=1
n=(-1+y) /2
3=(0+y)/2
y=6
hence, the fourth vertex is (1,6)
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