Math, asked by kodusrinvasrao, 3 months ago

4th vertex of the rhombus whose 3 consecutive vertices are (-4,-0),(3,-1),(2,6) is

1) (-5,7)

2) (7,-5)

3) (2,-5)

4)(5,-2)
i want the written answer please ​

Answers

Answered by seemabajpai1980
0

Answer:

(1, 6)

Step-by-step explanation:

diagonals of parallelogram bisect each other

let the point of intersection of diagonals be p(m,n)

m=(-4+2)/2 = -1

n=(0+6)/2 = 3

let the fourth vertex of parallelogram (x, y)

m=(3+x) /2

-1=(3+x) /2

x=1

n=(-1+y) /2

3=(0+y)/2

y=6

hence, the fourth vertex is (1,6)

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