Question

4u^+8u find the zeroes of the polynomial ​

Answer 1

Answer:

${4u}^{2} + 8u \\ 4u(u + 2) \\ u = 0 \: and \: u = - 2$

Hope it helps you friend.

Answer 2

4u^2+8u= 0

Divide by 4

u^2+2u= 0

u(u+2)=0

u=0/-2

#BAL #answerwithquality