Question

4u square + 8u how to solve this sum

Answer 1

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Answer 2

4u2 + 8u

We have, f(u) = 4u2 + 8u = 4u (u + 2)

For f(u) = 0,

Either 4u = 0 ⇒ u = 0

or u + 2 = 0 ⇒ u = –2

∴ The zeroes of 4u2 + 8u and 0 and –2

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