Question

4u²+8u find the alfa+beta and alfa×beta​

Answer 1

Answer:

p(x) = 4u²+8u

4u ( u + 2 ) = 0

[4u + 0 ] [ u + 2 ] ------> factorized form

hence ,

u = 0

u = -2

Here ,

a = 4

b = 8

c = 0

Relation between zeros and its coefficients :-

Sum of zeroes = 0 + -2 = - 2

= -b/a = -8/4 = -2

Product of zeroes = 0 x -2 = 0

= c/a = 0/4 = 0

Step-by-step explanation:

Answer 2

Answer:

Let f(u)=4u

2

+8u

To calculate the zeros of the given equation, put f(u)=0.

4u

2

+8u=0

4u(u+2)=0

u=0,u=−2

The zeros of the given equation is 0 and −2.

Sum of the zeros is 0+(−2)=−2.

Product of the zeros is 0×−2=0.

According to the given equation,

The sum of the zeros is,

a

−b

=

4

−(8)

=−2

The product of the zeros is,

a

c

=

4

0

=0

Hence, it is verified that,

sumofzeros=

coefficientofx

2

−coefficientofx

And,

productofzeros=

coefficientofx

2

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