Question

4u²+8u find the zeroes and verify their relationship btw the zeroes and the coefficient ​

Answer 1

Step-by-step explanation:

4u(u+2)

4u= 0 or u+2=0

u=0 or u = -2

relationship between the zeroes and coefficients

1. sum of zeroes = alpha+beta

-b/a= 0+(-2)

-8/4= 0-2

-2= -2

2. product of zeroes = (alpha)(beta)

c/a= 0(-2)

0/4=0

0=0