Question

4u²+8u Find the zeros of the indicated polynomials and check the relation between their zeros and coefficients

Answer 1

Answer:

The zeros of the polynomial $4u^2+8u$ are $u=0$ and $u=-2$

Step-by-step explanation:

Given the polynomial in a single variable $u$ ,

$P(u)= 4u^2+8u$

We can factorize $P(u)$ to find the zeros of the polynomial.

Since $4u$ is a common factor in both the terms, we have

$\implies P(u)=4u(u+2)$

Also,

$P(u)=0\\\\\implies 4u(u+2)=0\\\\\implies 4u=0 \ \ \ \ \ or \ \ \ \ u+2=0\\\\\implies u=0 \ \ \ \ \ or \ \ \ \ u=-2$

So zeros of the polynomial are 0 and -2.

The coefficient of $u^2$ is the square of $(-2)$ which is one of the zeros. The coefficient of $u$ is twice the sum of zeros of the polynomial and the constant term is square of the other zero, which is $u=0$.

Answer 2

Answer:

The zeros of the polynomial 4u ^ 2 + 8u are u = 0 and u = - 2

Step-by-step explanation:

hope it will help you have a great day bye:)