4usquare+8u find the zeroes of the quadrqtic polynomial and relationship ship between the zeroes and the coefficients
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Answer:
The zeroes of 4u²+8u are 0,-2
sum of zeroes=-8/4
product of zeroes=0/4
Step-by-step explanation:
Given,
4u²+8u=4u(u+2)
4u=0 (u+2)=0
u=0(4) , u=0-2
=0. u=-2
Therefore, the zeroes of 4u²+8u are 0,-2
sum of the zeroes=0+(-2)
=-2=-(coefficient of u)/coefficient of u²
=-8/4
product of the zeroes=0(-2)
=0=constant term/coefficient of u²
=0/4
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