Math, asked by swarnakanthi66048, 2 months ago

4usquare+8u find the zeroes of the quadrqtic polynomial and relationship ship between the zeroes and the coefficients

Answers

Answered by preethamvenkat
0

Answer:

The zeroes of 4u²+8u are 0,-2

sum of zeroes=-8/4

product of zeroes=0/4

Step-by-step explanation:

Given,

4u²+8u=4u(u+2)

4u=0 (u+2)=0

u=0(4) , u=0-2

=0. u=-2

Therefore, the zeroes of 4u²+8u are 0,-2

sum of the zeroes=0+(-2)

=-2=-(coefficient of u)/coefficient of u²

=-8/4

product of the zeroes=0(-2)

=0=constant term/coefficient of u²

=0/4

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