Question

4usqure+8u+0 solve by using Therom

Answer 1

Answer:

u = -2

u = 0

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Answer 2

Answer:

Here you go!

Step-by-step explanation:

4u2+8u=0

4u(u+2)=0

u(u+2)=0/4=0

Therefore u= 0,-2

Now:

From above using formula: ax2+by+c=0

a=4, b=8,c=0

Alpha=0

Beta=-2

(1) Sum of zeroes= Alpha + Beta

                               0+(-2)

                               =0

    Sum of zeroes= -b/a

                             =-8/4= -2

(2) Product of zeroes= Alpha x Beta [ Here x means multiply]

                                    = 0x-2 [ Here x means multiply]

                                    = 0

     Product of zeroes= c/a

                                   = 0/4 = 0 {Hence proved}

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