Question

(4x+1)^2+(2x+3)^2/4x^2+12x+9=61/36

Answer 1

hello mate!......

$given...... \\ \\ \frac{(4x + 1) {}^{2} + (2x + 3) {}^{2} }{4x {}^{2} + 12x + 9} = \frac{61}{36} \\ \frac{16x {}^{2} + 1 + 8x + 4x {}^{2} + 9 + 12x }{4x {}^{2} + 12x + 9} = \frac{61}{36} \\ \frac{20x {}^{2} + 20x + 10 }{4 {x}^{2} + 12x + 9} = \frac{61}{36} \\ \frac{10(2x {}^{2} + 2x + 1)}{4x {}^{2} + 12x + 9} = \frac{61}{36} \\ \frac{2x {}^{2} + 2x + 1 }{4x {}^{2} + 12x + 9} = \frac{61}{360} \\ 720x {}^{2} + 720x + 360 = 244x {}^{2} + 732x + 549 \\ 476x {}^{2} - 12x - 189 = 0 \\ hope \: it \: helps \: u$