(4x+1/3)^3 find the value
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Answered by
2
Hi ,
3^4x = 1/81
3^4x = 1/3⁴
3^4x = 3^-4
[ Since 1/a^n = a^-n ]
4x = -4
[ Since If a^m = a^n then m = n ]
x = ( - 4 )/4
x = - 1
I hope this helps you.
: )
3^4x = 1/81
3^4x = 1/3⁴
3^4x = 3^-4
[ Since 1/a^n = a^-n ]
4x = -4
[ Since If a^m = a^n then m = n ]
x = ( - 4 )/4
x = - 1
I hope this helps you.
: )
Answered by
0
Step-by-step explanation:
(4x)^3 × (1/3)
64x^3 + 1/27
x = 1/27 - 64
1×1 - 64 × 27 / 27
1- 1728 / 27
-1727 / 27
x^3 = -1727 / 27
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