(4x+1)(4x-1),Expand the given equation.
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(4x+1)(4x-1)
By using Identity III i.e. ( a + b ) ( a - b ) = a² - b²
(4x+1)(4x-1) =
= ( 4x )² - 1²
= 16x² - 1
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BONJOUR,
❤ ❤ ❤ ❤
we use identity here :
(a+b)(a-b) = a^2 - b^2

❤ ❤ ❤ ❤
we use identity here :
(a+b)(a-b) = a^2 - b^2
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