Math, asked by Apurva3872, 10 hours ago

(4x +1)(4x +1) find identies

Answers

Answered by suhail2070

0

Answer:

$= 16 {x}^{2} + 1 + 8x$

Step-by-step explanation:

$(4x + 1)(4x + 1) = {(4x + 1)}^{2} \\ \\ = {(4x)}^{2} + {1}^{2} + 2(4x)(1) \\ \\ = 16 {x}^{2} + 1 + 8x.$

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