Question

(4x-1)(4x-1) using identity

Answer 1

Answer:

Using identity : (a-b)^2 = (a)^2 - 2ab + (b)^2

= (4x-1)^2 = (4x)^2 - 2(4x)(1) + 1^2

= 16x^2 - 8x +1

Step-by-step explanation:

Hope it helps