Question

(4x+1/4x) cube plz tell this Question​

Answer 1

$\: \: \: \: \: \: {(4x + \frac{1}{4x} )}^{3} \\ \\ = {(4x)}^{3} + {( \frac{1}{4x} )}^{3} + 3.4x. \frac{1}{4x} (4x + \frac{1}{4x} ) \\ \\ = 64 {x}^{3} + \frac{1}{64 {x}^{3} } + 3(4x + \frac{1}{4x} ) \\ \\ = 64 {x}^{3} + \frac{1}{64 {x}^{3} } + 12x + \frac{3}{4x}$

Answer 2

Answer:

Q:- (4x + 1/4x)³

=> 64x³ + 1/ 64x³ ans.

Step-by-step explanation:

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