Question

4x^-12z+25=0 solve by factorization method​

Answer 1

Step-by-step explanation:

Given as 4x2 – 12x + 25 = 0 4x2 – 12x + 9 + 16 = 0 (2x)2 – 2(2x)(3) + 32 + 16 = 0 (2x – 3)2 + 16 = 0 [Since, (a + b)2 = a2 + 2ab + b2] (2x – 3)2 + 16 × 1 = 0 As we know, i2 = –1 ⇒ 1 = –i2 On substituting 1 = –i2 in the above equation, we get (2x – 3)2 + 16(–i2) = 0 (2x – 3)2 – 16i2 = 0 (2x – 3)2 – (4i)2 = 0 [On using the formula, a2 – b2 = (a + b) (a – b)] (2x – 3 + 4i) (2x – 3 – 4i) = 0 2x – 3 + 4i = 0 or 2x – 3 – 4i = 0 2x = 3 – 4i or 2x = 3 + 4i x = 3/2 – 2i or x = 3/2 + 2i ∴ The roots of the given equation are 3/2 + 2i, 3/2 – 2iRead more on Sarthaks.com - https://www.sarthaks.com/660909/solve-the-quadratic-equations-by-factorization-method-only-4x-2-12x-25-0

Answer 2

Answer:

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Step-by-step explanation:

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