Question

(4x^2-1) (16x^4+4x^2+1)​

Answer 1

Answer:

64x^6 - 1

Step-by-step explanation:

$(4 {x}^{2} - 1)(16 {x}^{4} + 4 {x}^{2} + 1)$

Using Identity

a³ - b³ = (a - b)(a²+ ab + b²)

$64 {x}^{6} - 1$

Answer 2

64x^6 - 1

Step-by-step explanation:

(4 {x}^{2} - 1)(16 {x}^{4} + 4 {x}^{2} + 1)(4x

2

−1)(16x

4

+4x

2

+1)

Using Identity

a³ - b³ = (a - b)(a²+ ab + b²)

64 {x}^{6} - 164x

6

−1

love u and hope it helps you