Question

(4x^2-1)(4x^2+1)(2x-1)(2x+1) evaluate

Answer 1

Step-by-step explanation:

=((4x^2−1)(4x^2+1)(2x−1))(2x+1)

=((4x^2−1)(4x^2+1)(2x−1))(2x)+((4x^2−1)(4x^2+1)(2x−1))(1)

=64x^6−32x^5−4x^2+2x+32x^5−16x^4−2x+1

=64x^6−16x^4−4x^2+1

Answer 2

Answer:

$64x^{6}-16x^{4}-4x^{2}+1$

Step-by-step explanation:

$(4x^{2} -1)(4x^{2} +1)(2x-1)(2x+1)\\= [(4x^{2})^{2} -1^{2}][(2x)^{2}-1^{2}]\\= (16x^{4}-1)(4x^{2}-1)\\= 64x^{6}-16x^{4}-4x^{2}+1\\\\Hope\ it \ helps\ :)\\Please\ mark\ my\ answer\ as\ the\ brainliest$