Question

(4x^2+1/x^2)=21 find x

Answer 1

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Answer 2

hey mate,...

here's your answer,...

$\frac{ {4x}^{2} + 1 }{ {x}^{2} } = 21 \\ {4x}^{2} + 1 = 21 {x}^{2} \\ 1 = 21 {x}^{2} - 4 {x}^{2} \\ 1 = 17 {x}^{2} \\ {x}^{2} = \frac{1}{17} \\ x = \frac{1}{ \sqrt{17} }$

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