4x^2+10x=150, find the x
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hello mate
4x^2+10x-150=0
taking 2 as common
so
2x^2+5x-75=0
2x^2-10x+15x-75
2x(x-5) +15(x-5)
(2x+15) (x-5)
after that
valve of x are
case 1
2x+15=0
x=-15/2
case 2
x-5=0
x=5
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hope it's help u
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