Question

4x^2-11x-3
please it is urgent
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Answer 1

Given :

$4 {x}^{2} - 11x - 3 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

$4 {x}^{2} - 11x - 3 = 0 \\ 4 {x}^{2} - 12x + x - 3 = 0 \\ 4x(x - 3) + 1(x - 3) = 0 \\ (x - 3)(4x + 1) = 0$

Hence,

$x_1 = 3 \\ x_2 = \frac{ - 1}{4}$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Answer 2

${\huge{\bold{\green{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

$\sf 4x^2 - 11x - 3$

find the zeros of the polynomial

${\huge{\bold{\green{\bigstar{\boxed{\boxed{\bf{Solution}}}}}}}}$

solve by middle term split

$\sf\implies 4x^2 -11x -3=0$

$\sf\implies 4x^2 -12x + x - 3= 0$

$\sf\implies 4x(x - 3)+1(x-3)= 0$

$\sf\implies(4x-1)(x-3) = 0$

zeros in the equation

$\sf\implies 4x+ 1 = 0$

$\sf\implies 4x= -1$

$\sf\implies x =\dfrac{-1}{4}$

_________________

$\sf\implies x-3 = 0$

$\sf\implies x= 3$

Zeros of the equation are :-

${\bold{\blue{\boxed{\bf{\dfrac{-1}{4}}}}}}$ And ${\bold{\blue{\boxed{\bf{3}}}}}$

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THANK YOU❤