Question

4x*2-12ax-y*2-z*2-2yz+9a*2

Answer 1

Answer:

$4 {x}^{2} - 12ax - {y}^{2} - {z}^{2} - 2yz + 9 {a}^{2} \\ = 4x {}^{2} - 12ax + 9 {a}^{2} - {y}^{2} - 2yz - {z}^{2} \\ = (4 {x}^{2} - 12ax + 9 {a}^{2}) - ( {y}^{2} + 2yz + {z}^{2}) \\ = (2 {x} ) {}^{2} - 2 \times 2x \times 3a + (3a {)}^{2} - ( {y}^{2} + 2yz + {z}^{2} ) \\ = (2x - 3a) {}^{2} - (y + z) {}^{2} \\ = (2x - 3a + y + z) (2x - 3a - y - z) \\ = (2x + y + z - 3a)(2x - y - z - 3a)$