Question

4x ^ 2 + 12x + 8 factorizar

Answer 1

Answer:

=4X^2 +8X+4X+8=0

=4X(X+2)+4(X+2)

=(x+2)(x+4)

x= -2, x= -4

Answer 2

Answer:

Solution :-

✪ 4x² + 12x + 8 = 0

➻ 4(x² + 3x + 2) = 0

➻ 4{x² + (2 + 1)x + 2} = 0

➻ 4{x² + 2x + x + 2} = 0

➻ 4{x(x + 2) + 1(x + 2)} = 0

➻ 4{(x + 2) (x + 1)} = 0

➻ (x + 2) (x + 1) = 0

➻ (x + 2) = 0

➻ x + 2 = 0

➻ x = - 2

Either,

➻ (x + 1) = 0

➻ x + 1 = 0

➻ x = - 1

∴ The answer of this question is x = - 2, - 1