Math, asked by anuragkumar9854, 1 year ago

4x^2+12xy+9y^2-8x-12y factorize it​

Answers

Answered by 17kat
41

Answer:

Step-by-step explanation:

4x^2  +  12xy + 9y^2 - 8x - 12y

(2x)^2 + 2(2x)(3y) + (3y)^2 - 8x - 12y              

(splitting of terms so as we get the formula of (a+b)^2              

(2x+3y)^2 - 8x - 12y

Answered by pulakmath007
16

 \sf 4 {x}^{2}  + 12xy + 9 {y}^{2}  - 8x - 12y   =  (2x  + 3y)(2x + 3y - 4)

Given :

 \sf 4 {x}^{2}  + 12xy + 9 {y}^{2}  - 8x - 12y

To find :

Factorise the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

 \sf 4 {x}^{2}  + 12xy + 9 {y}^{2}  - 8x - 12y

Step 2 of 2 :

Factorise the expression

We use the formula

(a + b)² = a² + 2ab + b²

Thus we get

 \sf 4 {x}^{2}  + 12xy + 9 {y}^{2}  - 8x - 12y

 \sf  =  {(2x)}^{2}  + 2.2x.3y +  {(3y)}^{2}  - 8x - 12y

 \sf  =  {(2x + 3y)}^{2}    - 8x - 12y

 \sf  =  {(2x + 3y)}^{2}    -4(2x  + 3y)

 \sf  =  (2x  + 3y)(2x + 3y - 4)

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