Question

4x^2-16x+16 [using identities] ​

Answer 1

4x2−16x+16=0

4x2−16x+16=0Divide both sides by 4.

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4−1−4=−5−2−2=−4

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4−1−4=−5−2−2=−4The solution is the pair that gives sum −4.

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4−1−4=−5−2−2=−4The solution is the pair that gives sum −4.a=−2b=−2

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4−1−4=−5−2−2=−4The solution is the pair that gives sum −4.a=−2b=−2(x2−2x)+(−2x+4).

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4−1−4=−5−2−2=−4The solution is the pair that gives sum −4.a=−2b=−2(x2−2x)+(−2x+4).(x2−2x)+(−2x+4)

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4−1−4=−5−2−2=−4The solution is the pair that gives sum −4.a=−2b=−2(x2−2x)+(−2x+4).(x2−2x)+(−2x+4)x(x−2)−2(x−2)

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4−1−4=−5−2−2=−4The solution is the pair that gives sum −4.a=−2b=−2(x2−2x)+(−2x+4).(x2−2x)+(−2x+4)x(x−2)−2(x−2)(x−2)(x−2)

4x2−16x+16=0Divide both sides by 4.x2−4x+4=0a+b=−4ab=1×4=4−1−4=−5−2−2=−4The solution is the pair that gives sum −4.a=−2b=−2(x2−2x)+(−2x+4).(x2−2x)+(−2x+4)x(x−2)−2(x−2)(x−2)(x−2)(x−2)2

x=2