Question

(4x+2)^2+16(4x+2)+80
factorise
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Answer 1

Correction:

» (4x + 2)² + 16 (4x + 2) - 80

Answer:

» (4x + 2)² + 16 (4x + 2) - 80

Substitute (4x + 2) = y

= y² + 16y - 80

= y² + 20y - 4y - 80

= y (y + 20) - 4 (y + 20)

= (y + 20) (y - 4)

Resubstitute y = (4x + 2)

= (4x + 22) (4x - 2)