Question

(4x-2)^2+6x=25 solve it please...
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Answer 1

$\huge\tt\colorbox{pink}{αղsաҽɾ}$

${(4x - 2)}^{2} + 6x = 25 \\ \\ = >(4 {x})^{2} - 2 \times 4x \times 2 + {(2)}^{2} + 6x = 25 \\ \\ = > 16 {x}^{2} - 16x + 4 + 6x = 25 \\ \\ = > 16 {x}^{2} - 10x + 4 = 25 \\ \\ = > 16 {x}^{2} - 10x = 25 - 4 \\ \\ = > 16 {x}^{2} - 10x = 21 \\ \\ = > 16 {x}^{2} - 10x - 21 = 0$

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