4x^2-3k+1=0 and roots are real and equal then k=?
Answers
Answered by
3
Answer:
4/3
Step-by-step explanation:
roots are real mean
by quadratic formula
b^2-4ac=0
(-3k)^2-4*4*1=0
9k^2-16=0
k^2=16/9
k=4/3
its the correct answer
please mark it as brainlliest :-)
Answered by
3
Step-by-step explanation:
For real and equal roots,
Discriminant equal to zero
i.e,
D=0
b^2-4ac = 0
(-3k)^2- 4(4)(1)= 0
9k^2=16
k^2=16/9
k= ± 4/3
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