Question

4x^2 – 3kx + 1 = 0
find the value of k for which the quadratic equation are real and equal roots.​

Answer 1

Answer:

4x^2-3kx+1=0

given that it' s roots are real and equal

b^2-4ac=0

=(3 k )^2-4(4)(1)=0

= (3 k)^ 2=16

= 9k^2=16

=K^2=16/9

=k=√16/9

=k=4/3

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