Question

4x^2+3x+5=0 please tell​

Answer 1

Step-by-step explanation:

x=-3+-√9-80

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8

x=3+-i√71

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8

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Answer 2

Answer:

Step-by-step explanation:

Given equation

4x ^2+3x+5=0

Dividing by 4

4x ^2/4 + 3x/4+ 5/4=0x ^2+ 3x/4+5/4 =0

We know that

(a+b) ^2=a ^2+2ab+b ^2

Here a=x

2ab= 3x/4

2b = 3/4

b = 3/8

Adding and subtracting (3/8)^2

x ^2 + 3x/4+5/4+(3/8)^2-(3/8)^2 = 0

(x+3/8)^2 + 5/4 - (3/8)^2 = 0

(x+3/8)^2= 9/64 - 5/4

(x+3/8)^2 = 9-80/64

(x+3/8)^2 = -71/64

Since square of any number cannot be negative

So, answer does not exist.

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