(4x^2-3y^2) (4x^2+3y^2) algebraic identities
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Hello there,
Here is your answer:
we know,
(a+b)(a-b)=a^2-b^2
therefore,
(4x^2-3y^2)(4x^2+3y^3)=(4x^2)^2-(3y^2)^2
which is equal to 16x^4-9y^4 which is our answer.
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