Question

4x^2-3y^2+4xy+4yz-z^2

guys pls help me to do this sum pls!!​

Answer 1

Step-by-step explanation:

$4x ^{2} - 3y {}^{2} + 4xy + 4yz + z {}^{2} \\ \\ 4x { }^{2} + z {}^{2} + 4yz + 4xy + 3y { }^{2} \\ \\( 2x + z) {}^{2} + z {}^{2} + 4xy$