Question

4x^2-4√3x+3 factorise​

Answer 1

Question :-

$4x {}^{2} - 4 \sqrt{3} x + 3 = 0$

What to find out = Roots of the equation?

Solution :-

Factorise by splitting middle term

$4x {}^{2} - 4 \sqrt{3} x + 3 = 0 \\ \\ 4 {x}^{2} - 2 \sqrt{3} x - 2 \sqrt{3} x + \sqrt{9} = 0 \\ \\ 2x(2x - \sqrt{3} ) - \sqrt{3} (2x - \sqrt{3} ) = 0 \\ \\ (2x - \sqrt{3} )(2x - \sqrt{3} ) = 0 \\ \\ (2x - \sqrt{3} ) {}^{2} =0 \\ \\ 2x - \sqrt{3 } = 0 \\ \\ 2x = \sqrt{3}$

Hence,

$x = \frac{ \sqrt{3} }{2} \: \: \: \: \: \: \: ans$

Related term:-

• An equation containing a single variable of degree 2. Its general form is ax^2 + bx + c = 0, where x is the variable and a, b, and c are constants (a ≠ 0).

Answer 2

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