Question

4x^2 + 4√3x + 4 = 0 by middle term split ​

Answer 1

Answer:

Step by step solution :

STEP

1

:

Equation at the end of step 1

((3 • (x4)) - 22x2) - 4 = 0

STEP

2

:

Equation at the end of step

2

:

(3x4 - 22x2) - 4 = 0

STEP

3

:

Trying to factor by splitting the middle term

3.1 Factoring 3x4-4x2-4

The first term is, 3x4 its coefficient is 3 .

The middle term is, -4x2 its coefficient is -4 .

The last term, "the constant", is -4

Step-1 : Multiply the coefficient of the first term by the constant 3 • -4 = -12

Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -4 .

-12 + 1 = -11

-6 + 2 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and 2

3x4 - 6x2 + 2x2 - 4

Step-4 : Add up the first 2 terms, pulling out like factors :

3x2 • (x2-2)

Add up the last 2 terms, pulling out common factors :

2 • (x2-2)

Step-5 : Add up the four terms of step 4 :

(3x2+2) • (x2-2)

Which is the desired factorization