Question

4x^2-46x-21=0 .find solution​

Answer 1

➲CORRECT QUESTION :

• $\sf {4x^2 - 44x +21 =0}$, Find out solution.

☯GIVEN :

• $\bf {4x^2 - 44x + 21 =0}$

☯TO FIND :

• The zeros of the quadratic equation.

➲SOLUTION :

$\implies {\sf{4x^2 - 44x + 21 = 0}}$

• By middle term splitting :

$\implies {\sf{4x^2 -2x - 42x +21= 0}}$

$\implies {\sf{2x \big(2x -1 \big) -21 \big(2x-1\big) = 0}}$

$\implies {\sf{\big(2x - 1 \big) \big(2x -21 \big) = 0}}$

$\implies{ \sf{\big(2x - 1 \big) = 0 \: , \: \big(2x-21 \big) = 0}}$

$\implies {\sf{2x = 0 + 1 \: , \: 2x = 0 + 21}}$

$\implies{\sf{2x = 1 \: , \: 2x = 21}}$

$\implies{\underline {\boxed{\red{\tt{x = \dfrac{ 1}{2} \: , \: x = \dfrac{21}{2}}}}}}$

$\huge{ \purple{ \therefore}}$ The zeros of the quadratic equation are $\bf{\dfrac{ 1}{2}}$ and $\bf{\dfrac{21}{2}}$.