Question

4x^2-4a^2x+(a^4-b^4)=0

Answer 1

Step-by-step explanation:

4x²–4a²x+a⁴–b⁴=0

4 ( x²–a² ) + (a²)²–(b²)²=0

–4(a²–x²) + (a²+b²)(a²–b²)=0

{(a+b)²–2ab}{(a+b)(a–b)}=4(a²–x²)