Question

4x^2 - 4a²x + (a^4 - b^4) = 0​

Answer 1

Answer:

refer to this :)

hope this will help....

Answer 2

Step-by-step explanation:

D = 16 a^4 - 16(a^4 - b^4)

= 16 b^4

x = [ 4a^2 + √(16b^4) ] / 8 = ( 4a^2 + 4b^2 )/8

= ( a^2 + b^2 ) / 2

or

x = [ 4a^2 - √(16b^4) ] / 8 = ( 4a^2 - 4b^2 )/8

= ( a^2 - b^2 ) / 2