4x∧2 - 4ax + a∧2 - b∧2 = 0 Solve by factorization method Plss help I ll brain list it
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Step-by-step explanation:
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Given :
- Quadratic equation : 4x²-4ax+a²-b²=0
To find :
- Roots by factorisation method.
Solution :
→4x²-4ax+a²-b²=0
- Arranging terms
→(4x²-4ax+a²)-(b²)=0
- Identity used :
» x²+2xy+y²=(x+y)²
→ [(2x)²-2×2x×a+a²]-(b)²
→ [2x-a]²-b²
- Identity used :
» a²-b² = (a+b)(a-b)
→ [(2x-a)+b][(2x-a)-b]
→[2x-a+b][2x-a-b]
Hence, on factorisation 4x²-4ax+a²-b²=0 gives
= 2x-a+b, 2x-a-b
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