Math, asked by muskaan7mehta, 9 months ago

4x∧2 - 4ax + a∧2 - b∧2 = 0 Solve by factorization method Plss help I ll brain list it

Answers

Answered by anushkagarg04
1

Answer:

(2x - a + b)(2x - a - b)

Step-by-step explanation:

4 {x}^{2}  - 4ax +  {a}^{2}  -  {b}^{2}  \\  {(2x - a)}^{2}  -  {(b)}^{2}  \\ (2x - a + b)(2x - a - b)

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Answered by GraceS
1

\sf\huge\bold{Answer:}

Given :

  • Quadratic equation : 4x²-4ax+a²-b²=0

To find :

  • Roots by factorisation method.

Solution :

→4x²-4ax+a²-b²=0

  • Arranging terms

→(4x²-4ax+a²)-(b²)=0

  • Identity used :

» x²+2xy+y²=(x+y)²

→ [(2x)²-2×2x×a+a²]-(b)²

→ [2x-a]²-b²

  • Identity used :

» a²-b² = (a+b)(a-b)

→ [(2x-a)+b][(2x-a)-b]

→[2x-a+b][2x-a-b]

Hence, on factorisation 4x²-4ax+a²-b²=0 gives

= 2x-a+b, 2x-a-b

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