Question

4x∧2 - 4ax + a∧2 - b∧2 = 0 Solve by factorization method Plss help I ll brain list it

Answer 1

Answer:

$(2x - a + b)(2x - a - b)$

Step-by-step explanation:

$4 {x}^{2} - 4ax + {a}^{2} - {b}^{2} \\ {(2x - a)}^{2} - {(b)}^{2} \\ (2x - a + b)(2x - a - b)$

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Answer 2

$\sf\huge\bold{Answer:}$

Given :

• Quadratic equation : 4x²-4ax+a²-b²=0

To find :

• Roots by factorisation method.

Solution :

→4x²-4ax+a²-b²=0

• Arranging terms

→(4x²-4ax+a²)-(b²)=0

• Identity used :

» x²+2xy+y²=(x+y)²

→ [(2x)²-2×2x×a+a²]-(b)²

→ [2x-a]²-b²

• Identity used :

» a²-b² = (a+b)(a-b)

→ [(2x-a)+b][(2x-a)-b]

→[2x-a+b][2x-a-b]

Hence, on factorisation 4x²-4ax+a²-b²=0 gives

= 2x-a+b, 2x-a-b