Question

4x^2-4ax-(a^2-b^2)=0
solve (with explanation)​ right answer will be marked as brainlist answer

Answer 1

Step-by-step explanation:

The given quadratic equation is 4x

2

−4ax+(a 2−b 2)=0

4x 2−4ax+(a+b)(a−b)=0

⇒4x 2+[−2a−2a+2b−2b]x+(a−b)(a+b)=0

⇒4x 2+(2b−2a)x−(2a+2b)x+(a−b)(a+b)=0

⇒4x 2+2(b−a)x−2(a+b)x+(a−b)(a+b)=0

⇒2x[2x−(a−b)]−(a+b)[2x−(a−b)]=0

⇒[2x−(a−b)][2x−(a+b)]=0

⇒2x−(a−b)=0,2x−(a+b)=0

⇒x= 2a+b

Answer 2

Answer:

answer for the given problem is given