Question

4x^2 +4bx-(a^2-b^2)
please help me

Answer 1

The answer is in the picture I am sending.
Plz mark as brainliest

Answer 2

4x² +4bx -(a²- b²)

x=[ -4b ± √[16b² + 4*4*(a² - b²)] ] ÷ 2*4

x= [ -4b ± √ 16b² +16a² - 16b² ] ÷ 8

x = [ -4b ± √16a² ] ÷ 8

x= [ -4b ± 4a ] ÷ 8

x= [ -b ± a ] ÷ 2

x= (-b-a) / 2 OR x = (-b + a) / 2

2x+a+b=0 OR ( 2x + b-a )=0

So ,,4x² +4bx -(a²- b²) = (2x + a + b) ( 2x + b - a )