4x^2-4p-(p^2-q^2) by quadratic formula
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Hi ,
compare 4x² -4px - ( p² - q² ) = 0 with
ax² + bx + c = 0
a = 4 , b = -4p , c = - ( p² - q² )
discreaminant = b² - 4ac
D = ( -4p )² - 4 ×4 × [ -(p² - q²)]
= 16 ( p² - p² - q² )
= - 16q²
we know that the quadratic formula ,
x = ( - b ± √D ) / 2a
= [ 4 ± √(-16q² ) ] / (2 × 4 )
= [ 4 ( 1 ± qi ) ] / 8
= ( 1 ± qi ) / 2
I hope this helps you.
:)
compare 4x² -4px - ( p² - q² ) = 0 with
ax² + bx + c = 0
a = 4 , b = -4p , c = - ( p² - q² )
discreaminant = b² - 4ac
D = ( -4p )² - 4 ×4 × [ -(p² - q²)]
= 16 ( p² - p² - q² )
= - 16q²
we know that the quadratic formula ,
x = ( - b ± √D ) / 2a
= [ 4 ± √(-16q² ) ] / (2 × 4 )
= [ 4 ( 1 ± qi ) ] / 8
= ( 1 ± qi ) / 2
I hope this helps you.
:)
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