Question

4x^2+4x-8=0 solve factor​

Answer 1

Answer:

$=4x^{2}+ 4x -8=0\\=4x^{2} +(8-4 )x-8\\=4x^{2} +8x-4x-8\\=4x(x-1)+8(x-1)\\=(4x+8)(x-1)$

please mark it as brainlist answer

Step-by-step explanation: