4x^2+4x-y^2+1 factorise
Answers
Answered by
1
Step-by-step explanation:
4x^2+4x+1-y^2
(2x+1)^2-y^2
(2x+1-y)(2x+1+y)
Answered by
1
Answer:
4x^2+4x-y^2+1
=4x^2+4x+1-y^2
=(2x)^2+2.2x.1+(1)^2-(y)^2
=(2x+1)^2-(y)^2
=(2x+1+y)(2x+1-y)
=(2x+y+1)(2x-y+1)
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