Question

4x^2+4x-y^2+1 factorise​

Answer 1

Step-by-step explanation:

4x^2+4x+1-y^2

(2x+1)^2-y^2

(2x+1-y)(2x+1+y)

Answer 2

Answer:

4x^2+4x-y^2+1

=4x^2+4x+1-y^2

=(2x)^2+2.2x.1+(1)^2-(y)^2

=(2x+1)^2-(y)^2

=(2x+1+y)(2x+1-y)

=(2x+y+1)(2x-y+1)