Math, asked by panesarh989, 10 months ago

4x^2+4y^2+2x-2y bbbbbbbbbbbbbbbbb​

Answers

Answered by RiceGumxMasterRyan
0

4x^2+4y^2+2x-2y

\mathrm{Rewrite\:}4\mathrm{\:as\:}2\cdot \:2\mathrm{Rewrite\:}4\mathrm{\:as\:}2\cdot \:2=2\cdot \:2x^2+2\cdot \:2y^2+2x-2y=2\left(2x^2+2y^2+x-y\right)

=2\left(2x^2+2y^2+x-y\right)

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Answered by SweetPoison7
0

4x^2+4y^2+2x-2y

\mathrm{Rewrite\:}4\mathrm{\:as\:}2\cdot \:2\mathrm{Rewrite\:}4\mathrm{\:as\:}2\cdot \:2=2\cdot \:2x^2+2\cdot \:2y^2+2x-2y=2(2x^2+2y^2+x-y)Rewrite4as2⋅2Rewrite4as2⋅2=2⋅2x

2

+2⋅2y

2

+2x−2y=2(2x

2

+2y

2

+x−y)

=2(2x^2+2y^2+x-y)=2(2x

2

+2y

2

+x−y)

Hope this helps!!!!

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Thanks!!!!!!

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