Math, asked by raunaksingh6201, 9 months ago

4x^2+6x-4=0 solved factor and completing the square​

Answers

Answered by Anonymous
3

Answer:

4x²+ 6x - 4 =0

2xb = 6x

2b =. 6

b = 6/2

b² = (6/2)²

4x² + 6x - 4 =0 divide by 4

16 x² + 24 x - 16 =0

16 x²+24 x = 16

Add (6/2)²on both sides

16 x² + 24 x + (6/2)² = 16 + (6/2)²

(4x²) + 2 (2x)(6/2) + (6/2)² = 16 + 36 /4

It is in the form of (a+b)²

(4x + 6/2)² = 64 + 36/4

(4x + 6/2)² = 100 /4

(4x + 6/2 )² = 25

(4x + 6/2). = ±√25

4x + 3 = ±5.

4x = +5- 3 4x = -5 -3

4x = 2 4x = -8

x= 2/4. x= -8/4

x= 1/2. x= -2

I hope it will help you mate!

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