4x^2+7x+2=0 solve by completing square methode
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Solution :
4x² + 7x + 2 = 0
Divide each term by 4 , we get
=> x² + 7x/4 + 1/2 = 0
=> x² + 2*x*(7/8) = -1/2
=> x² + 2*x*(7/8) + ( 7/8 )² = -1/2 + ( 7/8 )²
=> ( x + 7/8 )² = -1/2 + 49/64
=> ( x + 7/8 )² = ( -32 + 49 )/64
=> ( x + 7/8 )² = 17/64
=> x + 7/8 = ± √17/8
=> x = -7/8 ± √17/8
=> x = ( -7 ± √17 )/8
•••••
4x² + 7x + 2 = 0
Divide each term by 4 , we get
=> x² + 7x/4 + 1/2 = 0
=> x² + 2*x*(7/8) = -1/2
=> x² + 2*x*(7/8) + ( 7/8 )² = -1/2 + ( 7/8 )²
=> ( x + 7/8 )² = -1/2 + 49/64
=> ( x + 7/8 )² = ( -32 + 49 )/64
=> ( x + 7/8 )² = 17/64
=> x + 7/8 = ± √17/8
=> x = -7/8 ± √17/8
=> x = ( -7 ± √17 )/8
•••••
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