Question

4x^2-8x+3=0 factor method.
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Answer 1

Answer:

Step-by-step explanation:

4x^2-8x+3=0

4x²-2x-6x+3 = 0

2x(2x-1)-3(2x-1 )= 0

(2x-1)(2x-3)=0

Thus either (2x-1) or (2x-3) =0.

2x-1=0

2x=1

x=1/2

2x-3 =0

2x=3

x= 3/2

Thus , x =1/2 or 3/2

Answer 2

Step-by-step explanation:

4x^2-8x+3=0

We will factorise it .

or 4x^2-2x-6x+3=0

or 2x(2x-1)-3(2x-1)=0

or (2x-1)(2x-3)=0

Thus either (2x-1) or (2x-3) =0.

2x-1=0

or 2x=1

or x=1/2

2x-3 =0

or 2x=3

or x= 3/2

Thus , x =1/2 or 3/2