Question

4x^2-8x+4 factorization​

Answer 1

Step-by-step explanation:

4x^2-8x+4 or 4x^2-8x+4

=4(x^2-2x+1) =4x^2-4x-4x+4

=4(x-1)^2 =4x(x-1)-4(x-1)

=(x-1)(4x-4)

or 4x^2-8x+4

=(2x)^2-2×2x×2+(2)^2

=(2x-2)^2

you can factories it by any of the above way.