Question

4x^2 + 8x + 4 find the value of x​

Answer 1

Answer:

$x = - 1$

Step-by-step explanation:

${4x}^{2} + 8x + 4 \\ {4x}^{2} + 4x + 4x + 4 \\ 4x(x + 1) + 4(x + 1) \\ (4x + 4)(x + 1) \\ equating \: \: each \: \: to \: \: 0 \\ x + 1 = 0 \\ x = - 1$

$4x + 4 = 0 \\ 4x = - 4 \\ x = \frac{ - 4}{4} \\ x = - 1$

IF U FOUND IT HELPFUL THEN PLS MARK AS BRAINLIEST

Answer 2

Answer:

(4x+4)(x+1)

Step-by-step explanation:

4x^2+8x+4

=4x^2+(4+4)x+4

=4x^2+4x+4x+4

=4x(x+1)+4(x+1)

=(4x+4)(x+1)