Question

4x^2-8x+4 pls solve

Answer 1

Hi mate

here is ur answer⬇️⬇️

4X^2-8X+4=0. ( divided by 4)
X^2-2X+1=0
X^2-X-X+1=0
X(X-1)-1(X-1)=0
(X-1)(X-1)=0

➡️X=1
➡️X=1

I hope this will help you

⚛️mark as brainliest ⚛️

Answer 2

4x²-8x+4=4x²-4x-4x+4
= 4x(x-1)-4(x-1)
taking x-1 as common,
= (4x-4)(x-1)